Water is poured into a beaker with a bottom area of 20 cm2 up to a height of 10 cm. How many grams are poured?

Water is poured into a beaker with a bottom area of 20 cm2 up to a height of 10 cm. How many grams are poured? What is the pressure of the water at the bottom of the beaker?

Let’s give the data to us in the SI system:
S = 20 cm² = 0.002 m²
h = 10 cm = 0.1 m
Let’s write an expression to determine the mass by specific gravity (density):
m = ρ * V, where ρ is the density of the substance (ρ = 1000 kg / m3 according to the reference book), V is the volume of the substance.
We find the volume as the volume of the cylinder:
V = S * h
Hence:
m = ρ * V = ρ * S * h = 1000 * 0.002 * 0.1 = 0.2 kg
According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.
P = ρ * g * h = 1000 * 9.8 * 0.1 = 980 Pa
Answer: the mass of water is 0.2 kg, the pressure at the bottom is 980 Pa.