Water makes Q = 2.7 * 10 ^ 6. J. The water temperature was 70 °. Find the mass of vapor.

univerkov | August 2, 2021 | education

Initial data: Q (work done by water) = 2.7 * 10 ^ 6 J; t0 (initial temperature) = 70 ºС.

Reference values: t (vaporization temperature, n.o.) = 100 ºС; C (specific heat) = 4200 J / (kg * K); L (specific heat of vaporization) = 2.3 * 10 ^ 6 J / kg.

The mass of the vapor is determined from the formula: Q = C * m * (t – t0) + L * m = m * (C * (t – t0) + L), whence m = Q / (C * (t – t0) + L).

Calculation: m = 2.7 * 10 ^ 6 / (4200 * (100 – 70) + 2.3 * 10 ^ 6) = 1.11 kg.

Answer: The mass of steam is 1.11 kg.

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