Water vapor of centigrade weighing 5 kg is condensed. What amount of heat is released in this case?

Problem data: m (mass of water vapor taken in centigrade) = 5 kg.

Reference values: L (specific heat of condensation of water vapor) = 2.3 * 10 ^ 6 J / kg.

The heat released during the condensation of 5 kg of taken centigrade water vapor is determined by the formula: Q = L * m.

Let’s calculate: Q = 2.3 * 10 ^ 6 * 5 = 11.5 * 10 ^ 6 J (11.5 MJ).

Answer: During the condensation of 5 kg of taken centigrade water vapor, 11.5 MJ of heat should have been released.