Water was added to 40 g of sulfur (VI) oxide. Calculate what mass of sulfuric acid was formed in this case.

1. We write down the equation of the proceeding reaction:

SO3 + H2O = H2SO4;

2.find the chemical amount of sulfur oxide:

n (SO3) = m (SO3): M (SO3);

M (SO3) = 32 + 3 * 16 = 80 g / mol;

n (SO3) = 40: 80 = 0.5 mol;

3.Calculate the amount and mass of the formed acid:

n (H2SO4) = n (SO3) = 0.5 mol;

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 0.5 * 98 = 49 g.

Answer: 49 g.