Water was poured into a saucepan with a mass of 300 g and a volume of 1 liter.

Water was poured into a saucepan with a mass of 300 g and a volume of 1 liter. The initial temperature of the pan with water was 15 degrees. It took 368.73 kJ to heat the water in the pan to a boil. What material the pan is made of.

mk = 300 g = 0.3 kg.

Vw = 1 l = 1 * 10-3 m3.

t1 = 15 ° C.

t2 = 100 ° C.

Q = 368.73 kJ = 368730 J.

Cw = 4200 J / kg * ° C.

ρ = 1000 kg / m3.

Ck -?

In order to find what material the pan is made of, it is necessary to find the specific heat capacity of the pan substance Ck and, according to the table of the specific heat capacity of the substances, determine which substance it is.

Q = Cw * mw * (t2 – t1) + Ck * mk * (t2 – t1).

Ck * mk * (t2 – t1) = Q – Cw * mw * (t2 – t1).

Ck = (Q – Cw * mw * (t2 – t1)) / mk * (t2 – t1).

We express the mass of water in the pan mw by the formula: mw = ρ * Vw.

Cc = (Q – Cw * ρ * Vw * (t2 – t1)) / mc * (t2 – t1).

Cc = (368730 J – 4200 J / kg * ° C * 1000 kg / m3 * 1 * 10-3 m3 * (100 ° C – 15 ° C)) / 0.3 kg * (100 ° C – 15 ° C ) = 460 J / kg * ° C.

According to the table of specific heat of substances, the specific heat Cc = 460 J / kg * ° C corresponds to the substance iron.

Answer: The pan is made of iron.