Water weighing 5 kg at 90 * C was poured into a cast-iron pot weighing 2 kg at a temperature of 10 * C
| August 1, 2021 | education
Water weighing 5 kg at 90 * C was poured into a cast-iron pot weighing 2 kg at a temperature of 10 * C. What is the temperature of the water?
Given: m1 = 5 kg; Cw = 4200 J / (kg * K); t1 = 90 ºC; m2 = 2 kg; Cch = 540 J / (kg * K); t2 = 10 ºC.
Cв * m1 * (t1 – t) = Сч * m2 * (t – t2).
4200 * 5 * (90 – t) = 540 * 2 * (t – 10).
4200 * 5 * (90 – t) = 540 * 2 * (t – 10).
1890000 – 21000t = 1080t – 10800.
22080t = 1900800 and t = 1900800/22080 = 86 ºC.
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