Water weighing 500 g is at a temperature of 0 what amount of heat will be released

Water weighing 500 g is at a temperature of 0 what amount of heat will be released into the surrounding space if the water is taken outside where the temperature is -10.

To determine the amount of heat released into the surrounding space, we use the formula: Q = Q1 (ice formation) + Q2 (ice cooling) = m * (λ + Сl * Δt).

Variables and constants: m is the mass of water (m = 500 g = 0.5 kg); λ – beats heat of crystallization of water (λ = 340 * 10 ^ 3 J / kg); Sl – beats. heat capacity of ice (Cl = 2.1 * 10 ^ 3 J / (kg * K)); Δt – change in ice temperature (Δt = 10 ºС).

Let’s make a calculation: Q = m * (λ + Сl * Δt) = 0.5 * (340 * 10 ^ 3 + 2.1 * 10 ^ 3 * 10) = 180.5 * 10 ^ 3 J.

Answer: 180.5 kJ of heat will be released.