Water weighing 600 g was heated from 20C to 50C. How much energy is used to heat the water.

Problem data: m (mass of heated water) = 600 g (0.6 kg); t1 (temperature before heating) = 20 ºС; t2 (final water temperature) = 50 ºС.

Reference values: Sv (specific heat capacity of water) = 4200 J / (kg * ºС).

The consumed thermal energy for heating water is determined by the formula: Q = Cw * m * (t2 – t1).

Calculation: Q = 4200 * 0.6 * (50 – 20) = 75 600 (75.6 kJ).

Answer: 75.6 kJ of thermal energy was consumed.



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