Water with a mass of 5 kg and a temperature of 80 was mixed with water with a mass of 3 kg
Water with a mass of 5 kg and a temperature of 80 was mixed with water with a mass of 3 kg and a temperature of 40. find the temperature of the water that was formed during the mixing of all this.
To find the value of the water temperature obtained during the considered mixing, we use the equality: Cw * mt * (tcm – tt) = Cw * mg * (tg – tcm); mt * (tcm – tt) = mg * (tg – tcm).
Variables: mt is the mass of warm water (mt = 3 kg); tт – temperature of warm water (tт = 40 ºС); mg is the mass of hot water (mg = 5 kg); tg – hot water temperature (tg = 80 ºС).
Let’s make a calculation: 3 * (tcm – 40) = 5 * (80 – tcm).
3tcm – 120 = 400 – 5tcm.
5tcm + 3tcm = 400 + 120.
8tcm = 520 and tcm = 65 ºС.
Answer: After the considered mixing, the water temperature became equal to 65 ºС.