Water with a volume of 10 liters was heated from 40 to 100. How much heat was transferred to the water

Water with a volume of 10 liters was heated from 40 to 100. How much heat was transferred to the water? (specific heat capacity of water 4200 J / kg)

To find the amount of heat transferred to the taken water, we use the formula: Q = C * m * Δt = C * ρw * V * (t – t0).

Variables and constants: C – beats. heat capacity of water (C = 4200 J / (kg * K)); ρw is the density of the taken water (ρw = 1000 kg / m3); V is the volume of water (V = 10 l = 0.01 m3); t – final temperature (t = 100 ºС); t0 – temperature before heat transfer (t0 = 40 ºС).

Calculation: Q = C * ρw * V * (t – t0) = 4200 * 1000 * 0.01 * (100 – 40) = 2.52 * 10 ^ 6 J.

Answer: 2.52 MJ of heat was transferred to water.