Waves have formed on the surface of the pond, and a small floating object rises and falls six times in 15 seconds.

| February 19, 2021 | education

Waves have formed on the surface of the pond, and a small floating object rises and falls six times in 15 seconds. Determine the speed of waves propagating through the pond if the distance between adjacent ridges is 40 cm.

n = 6 – the number of wave oscillations during the time interval t;

t = 15 seconds – time interval;

l = 40 centimeters – the distance between adjacent ridges (wavelength).

It is required to determine u (m / s) – the speed of wave propagation.

We will convert the units of measurement of length to the SI system:

l = 40 cm = 40 * 10-2 = 40/100 = 0.4 meters.

Let’s find the frequency of the wave oscillations:

v = n / t = 6/15 = 0.4 Hertz.

Then the wave propagation speed will be equal to:

u = l * v = 0.4 * 0.4 = 0.16 m / s (meters per second).

Answer: the wave propagation speed is 0.16 m / s.



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