We calculated the mass of acetic acid that can react with sodium hydroxide solution weighing 200 g

| February 13, 2021 | education

We calculated the mass of acetic acid that can react with sodium hydroxide solution weighing 200 g with a mass fraction of NaOH of 10%.

We compose the reaction equation: CH3COOH + NaOH = CH3COONa + H2O.
1) Find the mass of the sodium hydroxide solute in its solution. To do this, multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 200 * 10/100 = 20g.
2) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
3) The amount of alkali substance: 20/40 = 0.5 mol.
4) According to the reaction equation, one mole of acetic acid accounts for one mole of hydroxide. This means that the amount of acid substance is equal to the amount of alkali substance and is equal to 0.5 mol.
5) Weight of acetic acid: 0.5 * (12 + 3 + 12 + 16 + 16 + 1) = 0.5 * 60 = 30g – answer.



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