We crossed a red-eyed gray Drosophila, heterozygous for two alleles, with a red-eyed Black Drosophila

We crossed a red-eyed gray Drosophila, heterozygous for two alleles, with a red-eyed Black Drosophila, heterozygous for the first allele. Red eyes and gray body are dominant signs, cherry eyes and black body are recessive signs. Determine the genotypes of the parents, gametes, the numerical splitting of the offspring by phenotype and genotype.

Let’s designate the gene that causes the development of red eyes in Drosophila as B, and the gene for cherry eyes as b. Let’s designate the gene for the gray body color of Drosophila as C, then the gene for the black body color of this fly will be c.

Diheterozygous red-eyed gray Drosophila, according to the introduced designations – ВвСс. It produces four types of germ cells – bc, BC, bC and BC.

Red-eyed black fruit fly, by condition, is heterozygous for the gene for eye color – Bbcc. Such a fly produces two types of germ cells – Bc and bc.

The offspring from crossing the described individuals will include the following options:

cubs with a black body and red eyes (2ВвСС, ВВ cc);

cubs with a gray body and red eyes (BB Cc, 2BbCc);

cubs with black bodies and cherry eyes (bbcc);

cubs with a gray body and cherry eyes (bbCc).

Thus, the splitting will be 3: 3: 1: 1.