We hung the load on the dynamometer, its reading was equal to 24.5 Newtons. Determine the mass

We hung the load on the dynamometer, its reading was equal to 24.5 Newtons. Determine the mass of the load suspended from the dynamometer.

F = 24.5 N.
g = 9.8 m / s ^ 2.
m -?
The body that hangs on the dynamometer is acted upon by 2 forces: the force of gravity m * g, directed vertically downward, and the force of elasticity of the spring of the dynamometer F, directed vertically upward.
Since the load is in equilibrium, these forces compensate each other: F = m * g.
m = F / g.
m = 24.5 N / 9.8 m / s ^ 2 = 2.5 kg.
Answer: the weight of the body that hangs on the dynamometer is m = 2.5 kg.