We mixed 1.12 liters of chlorine and 2.24 liters of hydrogen. The mixture was set on fire. How much hydrogen

We mixed 1.12 liters of chlorine and 2.24 liters of hydrogen. The mixture was set on fire. How much hydrogen chloride was formed as a result of the reaction?

Getting hydrochloric acid.
Cl2 + H2 = 2HCl.
Let’s determine the number of moles of substances.
n (Cl2) = V / Vm = 1.12 L / 22.4 mol / L = 0.05 mol.
n (H2) = 2.24 L / 22.4 mol / L = 0.1 mol.
The amount of hydrogen will be in excess, the calculation is based on chlorine.
If from 22.4 liters of chlorine 44.8 liters of acid are formed, then from 1.12 liters – xl.
V (HCl) = 44.8 mol / L * 1.12 L / 22.4 mol / L = 2.24 L.