Weights are suspended on a thread thrown over a fixed block. The mass of the larger load is 20 kg.

Weights are suspended on a thread thrown over a fixed block. The mass of the larger load is 20 kg. Find the mass of the second load if the system is moving with an acceleration of 2m / s ^ 2.

Given:
m1 = 20 kg – the mass of the first cargo,
a = 2 m / s ^ 2 – acceleration of the system of loads,
g = 10 m / s ^ 2 – acceleration of gravity.
To find:
m2 is the mass of the second cargo.
We write Newton’s second law for a system of loads: (m1 + m2) a = m1g – m2g
From this equation we obtain the formula for finding the mass of the second load:
m2 = m1 (g – a) / (g + a)
We substitute the values of known quantities into the equation:
m2 = 20 kg x (10 m / s ^ 2 – 2 m / s ^ 2) / (10 m / s ^ 2 + 2 m / s ^ 2) = 13.3 kg.
Answer: the mass of the second load is 13.3 kg.