Weights weighing 100 g and 500 g are suspended at the ends of a light rod 60 cm long. At what point should

Weights weighing 100 g and 500 g are suspended at the ends of a light rod 60 cm long. At what point should this rod be suspended so that it is in equilibrium in a horizontal position.

According to the leverage rule:
F1 * l1 = F2 * l2,
Where
F1 = m1 * g and F2 = m2 * g are the forces acting on the end of the bar,
g is the acceleration of gravity, and
l1 and l2 are the shoulders of these forces;
According to the condition of the problem:
l1 + l2 = 60cm = 0.6m
and
m1 * g * l1 = m2 * g * l2;
From here we get:
l1 = l2 * (m2 / m1);
l1 = 5 * l2;
5 * l2 + l2 = 0.6m;
l2 = 0.1m;
The rod should be suspended at a point 0.1m = 10cm from the heavy load.