What acceleration when moving from a standstill will the electric locomotive impart to the train with a mass

What acceleration when moving from a standstill will the electric locomotive impart to the train with a mass of 3250 tons, if at the same time it develops a traction force of 650 kn? The force of resistance to movement is 162.5 kn.

m = 3250 t = 3250000 kg.

Ft = 650 kN = 650,000 N.

Fcopr = 162.5 kN = 162500 N.

a -?

According to 2 Newton’s law, the acceleration of a body a is equal to the ratio of the resultant force Fр to the mass of the body: a = Fр / m.

The resultant of all forces Fр is the vector sum of all forces that act on the body: F = Fт + Fсopr.

Since the traction force Ft is directed towards the movement of the body, and the resistance force is in the opposite direction: Fr = Ft – Fcopr.

a = (Fт – Fcopr) / m.

a = (650,000 N – 162500 N) / 3250,000 kg = 0.15 m / s2.

Answer: the electric locomotive gives the train an acceleration a = 0.15 m / s2.