What acceleration will an electron receive in an electric field if the distance between the anode and cathode is 4 mm

What acceleration will an electron receive in an electric field if the distance between the anode and cathode is 4 mm, the electron mass is 9.1×10 ^ -28 g, the electron charge is 1.6×10 ^ -19 C, the voltage is 150 V.

S = 4 mm = 4 * 10 ^ -3 m.

m = 9.1 * 10 ^ -28 g = 9.1 * 10 ^ -31 kg.

q = 1.6 * 10 ^ -19 Cl.

U = 150 V.

a -?

Let’s write Newton’s 2 law for an electron: m * a = F, where m is the electron mass, a is the electron acceleration, F is the force of the electrostatic field.

a = F / m.

The force F is found by the formula: F = A / S, where A is the work of the electric field to move the electron, S is the movement of the electron.

a = A / S * m.

We express the work of the field A by the formula: A = q * U, where q is the electron charge, U is the voltage between the electrodes.

a = q * U / S * m.

a = 1.6 * 10 ^ -19 C * 150 V / 4 * 10 ^ -3 m * 9.1 * 10 ^ -31 kg = 2.275 * 10 ^ 15 m / s ^ 2.

Answer: the acceleration of an electron is a = 2.275 * 10 ^ 15 m / s ^ 2.