What amount of a substance is contained in a gas if, at a pressure of 200 kPa and a temperature

What amount of a substance is contained in a gas if, at a pressure of 200 kPa and a temperature of 240K, its volume is 40 liters?

Data: P (gas pressure) = 200 kPa; T (absolute gas temperature) = 240 K; V (the volume that the gas will occupy) = 40 liters.

Reference values: R (universal gas constant) = 8.31 J / (mol * K).

SI: P = 200 kPa = 200 * 10 ^ 3 Pa; V = 40 l = 40 * 10-3 m3.

The amount of gas substance is determined according to the Mendeleev-Clapeyron law:

P * V = (m / M) * R * T = ν * R * T, whence ν = P * V / (R * T).

Calculation: ν = 200 * 10 ^ 3 * 40 * 10-3 / (8.31 * 240) ≈ 4 mol.

Answer: The gas contains 4 moles of a substance.