What amount of a substance is contained in a gas if at p = 200 kPa and T = 240 K its V = 40 liters?

univerkov | January 31, 2021 | education

Task data: P (gas pressure value) = 200 kPa (200 * 10 ^ 3 Pa); T (gas temperature) = 240 K; V (gas volume) = 40 l (40 * 10 ^ -3 m3).

Constants: R (universal gas constant) = 8.314 J / (K * mol).

The amount of substance contained in the gas is calculated from the formula (Mendeleev-Clapeyron’s law): P * V = (m / M) * R * T, where m / M = ν and ν = P * V / (R * T) …

Let’s make the calculation: ν = 200 * 10 ^ 3 * 40 * 10 ^ -3 / (8.314 * 240) = 4 mol.

Answer: The amount of gas substance is 4 mol.

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