What amount of alcohol taken at a temperature of 78 boiled away if 18 kJ of heat was reported to it?
| February 21, 2021 | education
The mass of alcohol that will boil away when a given amount of heat is given to it can be calculated from the formula (at a temperature of 78 ° C, the vaporization of ethyl alcohol begins): Q = L * m, where Q is the heat imparted to alcohol (18 kJ = 18 * 10 ^ 3 J ); L is the specific heat of vaporization of alcohol (905 kJ / kg = 905 * 10 ^ 3 J / kg).
Calculation: m = Q / L = 18 * 10 ^ 3 / (905 * 10 ^ 3) = 18/905 ≈ 0.02 kg (20 g).
Answer: 20 grams of alcohol will go into steam.
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