What amount of aluminum sulfate AL2 (SO4) 2 is contained in 171 mg of this substance?

To find out how much aluminum sulfate AL2 (SO4) 2 is contained in 171mg of this substance, you need:
N (Al2 (SO4) 3 = 0.171 g / 246 g / mol = 0.0006951 mol = 0.0007 mol
Answer: 0.0007 mol



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