What amount of CaO is formed when Ca interacts with 6 mol of O2?
| March 2, 2021 | education
Let’s make a chemical equation, not forgetting to put down the coefficients: 2Ca + O2 = 2CaO.
The amount of substance (n) will be denoted by X. Then, using the equation, we make the proportion: 6/1 = X / 2.
Find X: X = 6 * 2 = 12.
Since for X we designated the amount of substance, therefore: X = 12 mol.
Answer: n (CaO) = 12 mol.
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