What amount of carbon dioxide is formed during the decomposition of 200 g of calcium carbonate?
June 1, 2021 | education
| The decomposition reaction of limestone is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.
Let’s calculate the available chemical amount of calcium carbonate substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 200/100 = 2 mol;
This amount of calcium oxide and carbon dioxide will be synthesized.
Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 2 x 22.4 = 44.8 liters;
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