What amount of carbon monoxide (4) substance is formed during the decomposition

What amount of carbon monoxide (4) substance is formed during the decomposition of 100 g of calcium carbonate containing 20% of impurities?

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 100 x 0.2 / 100 = 0.2 mol;

This amount of calcium oxide and carbon dioxide will be synthesized.

Let’s calculate its volume. To do this, multiply the amount of substance in mol and the standard volume of 1 mol of gaseous substance, which is 22.4 liters.

V CO2 = 0.2 x 22.4 = 4.48 liters;