What amount of centigrade water vapor is required to heat 10 kg of water from 10 to 60 ° C?
| January 27, 2021 | education
Q = c * m1 * (60 ° C – 10 ° C) = L * m2 + c * m 2 * (100 ° C – 60 ° C)
c * m1 * 50 ° C = m2 * (L + c * 40 ° C)
m2 = c * m1 * 50 ° C / (L + c * 40 ° C)
m2 = 4200 J / (kg * ° C) * 10 kg * 50 ° C / (2.3 * 10⁶ J / kg + 4200 J / (kg * ° C) * 40 ° C) ≈ 0.85 kg
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