What amount of copper substance will be released during the interaction of 28 g of iron with a solution

| May 21, 2021 | education

What amount of copper substance will be released during the interaction of 28 g of iron with a solution of copper sulfate (2) according to the following reaction equation: Fe + CuSO4 = Cu + FeSO4

Given:
m (Fe) = 28 g

To find:
n (Cu) -?

Decision:
1) Write the equation of a chemical reaction:
Fe + CuSO4 => Cu ↓ + FeSO4;
2) Using the periodic system of D.I.Mendeleev, calculate the molar mass of KOH, which will be numerically equal to the molecular mass:
M (Fe) = Mr (Fe) = Ar (Fe) = 56 g / mol;
3) Calculate the amount of the substance Fe:
n (Fe) = m (Fe) / M (Fe) = 28/56 = 0.5 mol;
4) Determine the amount of Cu substance (taking into account the coefficients in the reaction equation):
n (Cu) = n (Fe) = 0.5 mol.

Answer: The amount of Cu substance is 0.5 mol.



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