What amount of copper sulfate (||) substance is formed as a result of the interaction of 40 g of copper

What amount of copper sulfate (||) substance is formed as a result of the interaction of 40 g of copper oxide (||) with 100 g of 49% sulfuric acid solution?

Given: Solution:
m (CuO) = 40g CuO + H2SO4 = CuSO4 + H2O
m (H2SO4) = 100g 1. Find the mass of pure sulfuric acid:
w (H2SO4) = 49% m (H2SO4) = m solution (H2SO4) x W (H2SO4) =
= 100 x 0.49 = 49 g
2. Find the amount of sulfuric acid substance:
n (H2SO4) = m (H2SO4) / М (H2SO4) = 49g / 98g / mol =
= 0.5 mol
3. Find the amount of copper sulfate substance:
n (CuSO4) = n (H2SO4) = 0.5 mol
(according to the equation, because in front of them are the same
coefficients).
Answer: 0.5 mol