What amount of heat did an aluminum bar weighing 200 g receive when heated from 20 degrees to 100?

Required heat for heating an aluminum bar:

Q = C * m * (tc – tn), where C is the specific heat capacity (for aluminum C2 = 920 J / (kg * K)), m is the mass of an aluminum bar (m = 200 g = 0.2 kg), tc – the final temperature of the aluminum bar (tc = 100 ºС), tн – the initial temperature of the aluminum bar (tn = 20 ºС).

Payment:

Q = C * m * (tc – tn) = 920 * 0.2 * (100 – 20) = 920 * 0.2 * 80 = 14720 J.

Answer: When heated, the aluminum bar received 14720 J of heat.



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