What amount of heat is absorbed by copper weighing 15 kg during melting, if its initial temperature is 53 degrees?

Q = Q1 + Q2.
Q1 = C * m * (tк – tн), where C is the specific heat capacity of copper (C = 385 J / (K * kg)), m is the mass of copper (m = 15 kg), tк is the melting point of copper (tк = 1083 ºС), tн – initial temperature (tн = 53 ºС).
Q2 = λ * m, where λ is the specific heat of fusion of copper (λ = 2.1 * 10 ^ 5 J / kg).
Let’s calculate the required energy:
Q = Q1 + Q2 = C * m * (tк – tн) + λ * m = 385 * 15 * (1083 – 53) + 2.1 * 10 ^ 5 * 15 = 5948250 + 3150000 = 9098250 J ≈ 9.1 MJ.
Answer: Copper will absorb 9.1 MJ of energy.