What amount of heat is absorbed by ice with a mass of 5 kg when melting

What amount of heat is absorbed by ice with a mass of 5 kg when melting if its temperature is 0 ° C? The specific heat of melting of ice is 340 kJ / kg

Formula for finding the amount of heat released during ice melting:

Q = lambda × m.

Lambda – specific heat of melting of ice, J / kg.

m – ice mass, kg.

Lambda is a tabular value and it is equal to 340 kJ / kg.

Ice weight 5 kg.

Q = 340 × 10 ^ 3 J / kg × 5 kg = 1700 × 10 ^ 3 J = 1.7 MJ.

Answer: the amount of heat released during ice melting is 1.7 MJ.



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