What amount of heat is absorbed when heating a steel part m = 10kg from temperature t1 = 100c to temperature t2 = 150c?

Task data: m (weight of the steel part taken) = 10 kg; t1 (initial temperature of the part) = 100 ºС; t2 (end temperature) = 150 ° C.

Reference values: Сс (specific heat capacity of steel) = 500 J / (kg * K).

The amount of heat that will be absorbed by the taken steel part during heating is determined by the formula: Q = Сс * m * (t2 – t1).

Calculation: Q = 500 * 10 * (150 – 100) = 250,000 J or 250 kJ.

Answer: When heated, the steel part taken will absorb 250 kJ of heat.