What amount of heat is needed to heat 10 kg water in an iron boiler 2 kg from a temperature
What amount of heat is needed to heat 10 kg water in an iron boiler 2 kg from a temperature of 10 degrees to a temperature of 50 degrees
Given:
m1 = 10 kilograms is the mass of water;
m2 = 2 kilograms – the mass of the iron boiler;
T1 = 10 degrees Celsius;
T2 = 50 degrees Celsius;
с1 = 4183 J / (kg deg) – specific heat capacity of water;
c2 = 450 J / (kg deg) – specific heat of iron.
It is required to find the amount of heat Q (Joule) for heating water in an iron boiler from temperature T1 to T2.
Energy required to heat water:
Q1 = m1 * c1 * (T2 – T1) = 10 * 4183 * (50 – 10) = 41830 * 40 = 1.67 * 10 ^ 6 Joules.
Energy required to heat an iron boiler;
Q2 = c2 * m2 * (T2 – T1) = 2 * 450 * (50 – 10) = 900 * 40 = 0.04 * 10 ^ 6 Joules.
The total energy will be equal to:
Q = Q1 + Q2 = 1.67 * 10 ^ 6 + 0.04 * 10 ^ 6 = 1.71 * 10 ^ 6 Joules = 1.71 MJ.
Answer: it is necessary to spend an amount of heat equal to 1.71 MJ.