What amount of heat is needed to heat 100g of lead from 300k to 320k? Specific heat capacity of lead c = 130J \ (kg • k)

univerkov | January 8, 2021 | education

Problem data: m (mass of heated lead) = 100 g (0.1 kg); t0 (temperature of taken lead before heating) = 300 K; t (temperature after heating) = 320 K.
Reference values: according to condition C (specific heat of lead) = 130 J / (kg * K).
The amount of heat that is needed to heat the lead is determined by the formula: Q = C * m * (t – t0).
Calculation: Q = 130 * 0.1 * (320 – 300) = 260 J.
Answer: To heat 100 g of lead, you need to spend 260 J of heat.

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