What amount of heat is needed to melt steel weighing 8220 kg, taken at a temperature of 72 C?
| February 9, 2021 | education
Data: m (mass of steel for melting) = 8220 kg; t (initial steel temperature) = 72 ºС.
Reference data: C (specific heat) = 500 J / (kg * K); tmelt (melting temperature of steel, depends on the chemical composition) = 1350 … 1535 (for the calculation we will take 1450 ºС); λ (specific heat of fusion) = 84 * 10 ^ 3 J / kg.
The formula for calculating the required heat is: Q = m * (C * (tpl – t) + λ).
Calculation: Q = 8220 * (500 * (1450 – 72) + 84 * 10 ^ 3) = 6354060000 J ≈ 6.35 GJ.
Answer: 6.35 GJ of heat is required.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
