Initial data: m (ether mass) = 20 g = 0.02 kg; tн (initial temperature of the ether) = 15 ºС.
Reference data: C (specific heat) = 2350 J / (K * kg)); L (specific heat of vaporization) = 0.4 * 10 ^ 6 J / kg; t steam (vaporization temperature) = 35 ° C.
Q = Q1 (heating) + Q2 (vaporization) = C * m * (tp – tn) + L * m = m * (C * (tp – tn) + L).
Let’s perform the calculation:
Q = 0.02 * (2350 * (35 – 15) + 0.4 * 10 ^ 6) = 8940 J.
Answer: For the vaporization of ether, 8940 J of heat is needed.
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