What amount of heat is released during the combustion of 6 coal (s) if the reaction equation is С + O2 = CO2 + 402.24KZhD
Let’s compose the equation of the coal combustion reaction.
C + O2 = CO2 + 402.24 kJ.
The reaction involves 1 mol of carbon.
1 mol (C) – 12 kg.
When burning 12 kg of coal, 402.24 kJ of heat is formed,
and when burning 6 kg of coal – Q kJ.
Let’s make the proportion:
12 kg – 402.24 kJ,
6 kg – Q kJ.
Q kJ = (6 × 402.24 kJ): 12 = 201.12 kJ.
Answer: Q kJ = 201.12 kJ.
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