What amount of heat is released during the complete combustion of a mixture of 2 kg of gasoline and 3 kg of alcohol?

Given:

m1 = 2 kilograms is the mass of gasoline;

m2 = 3 kilograms – the mass of alcohol;

q1 = 44 * 10 ^ 6 Joule / kilogram – specific heat of combustion of gasoline;

q2 = 30 * 10 ^ 6 Joule / kilogram is the specific heat of combustion of alcohol.

It is required to determine Q (Joule) – the amount of heat that will be released during the complete combustion of a mixture of gasoline and alcohol.

When gasoline burns, heat will be released, equal to:

Q1 = q1 * m1 = 44 * 10 ^ 6 * 2 = 88 * 10 ^ 6 Joules.

When alcohol burns, heat will be released, equal to:

Q2 = q2 * m2 = 30 * 10 ^ 6 * 3 = 90 * 10 ^ 6 Joules.

Energy will be released in total:

Q = Q1 + Q2 = 88 * 10 ^ 6 + 44 * 106 = 132 * 10 ^ 6 Joules = 132 MJ.

Answer: an energy equal to 132 MJ will be released.