What amount of heat is released during the condensation of water vapor with a mass of 10 kg

What amount of heat is released during the condensation of water vapor with a mass of 10 kg and at a temperature of 100 degrees and the resulting water is cooled to 20 degrees.

Initial data: m (mass of water vapor, water) = 10 kg; tн (initial temperature of water vapor) = 100 ºС; tк (final temperature of steam, water cooling) = 20 ºС.

Reference data: L (specific heat of vaporization) = 2.3 * 10 ^ 6 J / kg; C (specific heat capacity) = 4200 J / (kg * K).

The released amount of heat: Q = Q1 (condensation of water vapor) + Q2 (water cooling) = L * m + C * m * (tн – tк) = (L + C * (tн – tк)) * m.

Calculation: Q = (2.3 * 10 ^ 6 + 4200 * (100 – 20)) * 10 = 26.36 * 10 ^ 6 J = 26.36 MJ.