What amount of heat is released in 2.5 minutes in the filament of a lamp
| September 28, 2021 | education
What amount of heat is released in 2.5 minutes in the filament of a lamp, the resistance of which is 400 Ohm, with a current strength of 0.4 A in it?
Initial data: t (duration of the lamp) = 2.5 min (150 s); R (filament resistance) = 400 ohms; I (lamp current) = 0.4 A.
The amount of heat that will have time to be released into the filament is determined by the formula (we use the Joule-Lenz law): Q = I ^ 2 * R * t.
Calculation: Q = 0.4 ^ 2 * 400 * 150 = 9600 J (9.6 kJ).
Answer: For 2.5 minutes of lamp operation, 9.6 kJ of heat will be released.
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