What amount of heat is released when 1.5 tons of cast iron cools down from 70 ° C to 10 ° C?
| March 15, 2021 | education
m = 1.5 t = 1500 kg.
C = 540 J / kg * ° C.
t1 = 70 ° C.
t2 = 10 ° C.
Q -?
The amount of heat Q that is released when the substance cools is determined by the formula: Q = C * m * (t1 – t2), where C is the specific heat capacity of the substance, m is the mass of the substance, t1 is the initial temperature, t2 is the final temperature.
Q = 540 J / kg * ° C * 1500 kg * (70 ° C – 10 ° C) = 48600000 J = 48.6 MJ.
Answer: when the cast iron cooled down, heat energy Q = 48.6 MJ was released.
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