What amount of heat is released when 12 liters of water are converted into ice at 0 ° C?

Given: V (volume of water turned into ice) = 12 liters (in SI V = 12 * 10 ^ -3 m3); t (temperature of the obtained ice, initial temperature of the taken water) = 0 ºС.

Constants: ρw (density of taken water) = 1000 kg / m3; λ (specific heat of crystallization of water) = 3.4 * 10 ^ 5 J / kg.

The heat released during crystallization of 12 liters of water is determined by the formula: Q = λ * m = λ * ρw * V.

Calculation: Q = 3.4 * 10 ^ 5 * 1000 * 12 * 10 ^ -3 = 40.8 * 10 ^ 5 J or 4.08 MJ.

Answer: When 12 liters of water are converted into ice, 4.08 MJ of heat will be released.



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