What amount of heat is required for 2 kg ice, whose temperature is -15 ° C, to turn into steam at a temperature of 100 ° C?

What amount of heat is required for 2 kg ice, whose temperature is -15 ° C, to turn into steam at a temperature of 100 ° C? The specific heat of vaporization is 2.26 MJ / kg.

In this case, 4 processes occur:
Q_ {1} = c_ {1} m (0C – (- 15) C) – ice heating
Q_ {2} = Lm – ice melting
Q_ {3} = c_ {2} m (100C-0C) – water heating
Q_ {4} = rm – steam generation
where c_ {1} is the lot. heat capacity of ice c_ {2} – destiny. heat capacity of water
The sum of the results will be our final result
Q = 2100 * 2 * 15 + 332000 * 2 + 4200 * 2 * 100 + 2260000 * 2 = 63000 + 664000 + 840000 + 4520000 = 6087000 (J) = 6.08 MJ