What amount of heat is required to convert 200 g of water taken at a temperature

What amount of heat is required to convert 200 g of water taken at a temperature of 100 degrees Celsius into steam; the specific heat of water vaporization is 2.3 * 10 J / kg.

Initial data: m (mass of water to be converted into steam) = 200 g (0.2 kg); t (temperature at which water was taken) = 100 ºС (corresponds to the temperature of the beginning of vaporization).

Constants: according to the condition L (specific heat of vaporization of water) = 2.3 * 10 ^ 6 J / kg.

The formula for calculating the required heat will be as follows: Q = L * m = 2.3 * 10 ^ 6 * 0.2 = 460,000 J (460 kJ).

Answer: You will need 460 kJ of heat.