What amount of heat is required to heat 1 kg of mercury taken at 17 ° C to boil and turn into steam?

Given:
m = 1 kg;
c = 130 J / kg * degree Celsius;
t2 = 357;
t1 = 17.
Find: Q.
Decision:
To solve the problem, we will use this formula for finding heat.
Q = c * m * (t2-t1).
We know the values of all the variables, so to find the answer, we just need to substitute them in the formula and perform the calculations.
Q = 1 * 130 * (357-17) = 130 * 340 = 44200 J = 44, 2 kJ.
Answer: 44.2