What amount of heat is required to heat 250 g of water by 5 ° C per centigrade?

Task data: m (mass of taken water) = 250 g (0.25 kg); Δt (required change in water temperature during heating) = 5 ºС.

Reference values: Sv (specific heat of water) = 4200 J / (kg / K).

The thermal energy required for heating 250 g of water is determined by the formula: Q = Cw * m * Δt.

Calculation: Q = 4200 * 0.25 * 5 = 5 250 J.

Answer: To heat 250 g of water at 5 ºС, 5 250 J of thermal energy is required.




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