What amount of heat is required to heat steel with a volume of 0.5 m³ by 6 ºС? Density of steel 7800 kg / m

Initial data: Δt (change in steel temperature during heating) = 6 ºС; V (steel volume) = 0.5 m3.

Reference values: С (specific heat capacity of steel) = 500 J / (kg * ºС); by condition ρ (density of steel) = 7800 kg / m3.

1) We calculate the mass of the steel being heated: m = ρ * V = 7800 * 0.5 = 3900 kg.

2) The amount of heat required to heat the steel: Q = C * m * Δt = 500 * 3900 * 6 = 11,700,000 J (11.7 MJ).

Answer: To heat steel, 11.7 MJ of heat is required.