What amount of heat is required to heat water with a mass of 0.1 kg per 1 degree Celsius.

What amount of heat is required to heat water with a mass of 0.1 kg per 1 degree Celsius. 2. Calculate the amount of heat required for heating: a) a cast-iron iron weighing 1.5 kg to change its temperature by 200 degrees; b) an aluminum spoon weighing 50 g from 20 to 90 degrees; c) a brick fireplace weighing 2 tons from 10 to 40 degrees. 3. What amount of heat was released when the water cooled down, volume 20 liters, if the temperature changed from 100 to 50 degrees.

1) m = 0.1 kg. Δ t = 1 “C. c = 4200 J / (kg *” C). Q -?
The heat required for heating is determined by the formula: Q = c * m * Δ t. Q = 4200 J / (kg * “C) * 0.1 kg * 1” C = 420 J.
Answer: to heat water, you need Q = 420 J of the amount of heat.
2а) m = 1.5 kg. Δ t = 200 “C c = 540 J / (kg *” C). Q -?
Q = c * m * Δ t. Q = 540 J / (kg * “C) * 1.5 kg * 200” C = 162000 J.
Answer: to heat the iron you need Q = 162000 Joules of heat.
2b) m = 50 g 0.05 kg .. t1 = 20 “C. t2 = 90” C. c = 920 J / (kg * “C). Q -?
Q = c * m * (t2 – t1). Q = 920 J / (kg * “C) * 0.05 kg * (90” C – 20 “C) = 3220 J.
Answer: to heat an aluminum spoon, you need Q = 3220 J of heat.
2c) m = 2 t = 2000 kg. t1 = 10 “C. t2 = 40” C. Cc = 880 J / (kg * “C). Q -?
Q = c * m * (t2 – t1). Q = 880 J / (kg * “C) * 2000 kg * (40” C – 10 “C) = 52,800,000 J.
Answer: to heat the fireplace you need Q = 52,800,000 Joules of heat.
3) V = 20 l = 0.02 m ^ 3. ρ = 1000 kg / m ^ 3. t1 = 100 “C. t2 = 50” C. c = 4200 J / (kg * “C). Q -?
The heat that is released during cooling is determined by the formula: Q = c * m * (t1 – t2). m = V * ρ. Q = c * V * ρ * (t1 – t2). Q = 4200 J / (kg * “C) * 0.02 m ^ 3 * 1000 kg / m ^ 3 * (100” C – 50 “C) = 4200000 J.
Answer: during cooling, Q = 4200000 J of heat will be released.