What amount of heat is required to heat zinc weighing 5 kg from 90 degrees to 110 degrees (specific heat of zinc 400 J / kg * C)
| February 18, 2021 | education
The required amount of heat for heating zinc:
Q = C * m * (tк – tн); С is the specific heat capacity of zinc (we take according to the condition С = 400 J / (kg * К)), m is the mass of heated zinc (m = 5 kg), tк is the final temperature of zinc (tк = 110 ºС), tн is the initial temperature of zinc (tн = 110 ºС).
Let’s calculate the required amount of heat:
Q = С * m * (tк – tн) = 400 * 5 * (110 – 90) = 400 * 5 * 20 = 40,000 J = 40 kJ.
Answer: To heat 5 kilograms of zinc, 40 kJ of heat is required.
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